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#2795 Sep 30, 2003

Can someone tell me or give me an example on how to implement the following

formula. My problem is the negative number!

a = -20

b = 32

x = Value

y=a+bx

Thanks in advance, Scott

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#2796 Sep 30, 2003

Scott,

It is as easy as changing the formula to

y=bx-a

Assuming that x is never zero the above works.

a= -20

b=32

x=5

b*x = 160

y=160+ (-20) =140

y=160 - 20 = 140

Colin

On Wed, 1 Oct 2003 00:39:26 -0400, Scott Lingerfelt wrote:

:: Can someone tell me or give me an example on how to implement the

::following

::formula. My problem is the negative number!

::

:: a = -20

:: b = 32

:: x = Value

::

:: y=a+bx

::

:: Thanks in advance, Sco

--

cdb, bodgy1@... on 01.10.2003

I have always been a few Dendrites short of an Axon and believe me it

shows.

Light travels faster than sound. That's why some people appear bright

until they speak!

tt

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#2804 Oct 1, 2003

On Wednesday 01 Oct 2003 5:39 am, Scott Lingerfelt wrote: > Can someone tell me or give me an example on how to implement the following

> formula. My problem is the negative number!

>

> .a = -20

> .b = 32

> .x = Value

>

> .y=a+bx

>

Substituting for a and b gives

y = -20 + 32x

Rearranging gives

y = 32b - 20

So multiply b by 32 then subtract 20 from the result.

Ian